2Al + 6HCl = 2AlCl3 + 3H2
m ( чист. ) = m*80% = 13.5 *0.8 = 10.8 грамм
n=m/M = 10.8 / 27 = 0.4 моль
n(H2) = 0.6 моль
V(H2) = n*Vm = 0.6 * 22.4 = 13.44 литра
Ответ: 13,44 литра
1)6CO2+6H2O=C6H12O6+6O2
CH2OH-(CHOH)4-COH+H2=CH2OH-(CHOH)4-CH2OH
2)CH2OH(CHOH)4-COH+Ag2O=CH2OH-(CHOH)4-COOH+2Ag
CH2OH-(CHOH)4-COOH+NaOH=CH2OH-(CHOH)4-COONa+H2O
3)C6H12O6=2C2H5OH+2CO2
C2H5OH=C2H4+H2O
C6H12O6=H3C-CH-COOH+2CO2+2H2
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CH3
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2HNO3+Ca(OH)2=Ca(NO3)2+2H2O обмен
2. n(Cu(OH)2=m\Mr=39,2\98=0,4 моль
n(CuO)=n(Cu(OH)2= 0.4
m(CuO)=n*Mr=0,4*80=32 г
3. 4Li+O2=2Li2O соединение
Fe2O3+2Al=Al2O3+2Fe замещение
4. Fe+2HCl=FeCl2+H2 замещение
2Al+3Cl2=2AlCl3 соединение
2Ba + O₂ = 2BaO
BaO + H₂O = Ba(OH)₂
Ba(OH)₂ + H₂SO₄ = BaSO₄ + 2H₂O
BaSO₄ = BaO + SO₃
S + O₂ = SO₂
2SO₂ + O₂ = 2SO₃
SO₃ + H₂O = H₂SO₄
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O