Question

Решите пожалуйста 5x-15y/x^2-9y^2 6cb-18c^2/(b-3c)^3

Answer 1

$\frac{5x-15y}{x^{2}-9y^{2}}=\frac{5(x-3y)}{(x-3y)(x+3y)}=\frac{5}{x+3y}$

$\frac{6cb-18c^{2}}{(b-3c)^3}=\frac{6c(b-3c)}{(b-3c)^{3}}=\frac{6c}{(b-3c)^{2}}$