(-17tg4⁰ -2tg176⁰)/(4ctg274⁰-ctg94⁰)=
=(-17tg4⁰-2tg(180⁰-4⁰)/(4ctg(270⁰+4⁰)-ctg(90⁰+4⁰)=
=(-17tg4⁰+2tg4⁰)/(4tg4⁰-tg4⁰)=(-15tg4⁰)/3tg4⁰=-5;
AD=AH+HD=3+30=33
BH^2=BD^2-HD^2
BH^2=50^2-30^2
BH^2=1600
BH=40
Sпар= AD*BH=33*40=1320
ОТВЕТ= 1320
(1) f(x) = x² + x = x(x + 1)
(2) f(x0 + ∆x) = f(1 + 0,2) = f(1,2) = 1,2(1,2 + 1) = 1,2 × 2,2 = 2,64
(3) f(x0) = f(1) = 1(1 + 1) = 1 × 2 = 2
(4) ∆f(x) = f(x0 + ∆x) - f(x0) = f(1,2) - f(1) = 2,64 - 2 = 0,64
Ответ: ∆f(x) = 0,64