Question

помогите пж с лимитом

Answer 1

$\lim\limits _{x \to \infty}\Big (\frac{x+3}{x-2}\Big )^{x+3}=\lim\limits _{x \to \infty}\Big (\Big (1+\frac{5}{x-2}\Big )^{\frac{x-2}{5}}\Big )^{\frac{5(x+3)}{x-2}}=e^{\lim\limits _{x \to \infty}\frac{5x+15}{x-2}}=e^5$