Question

Найти частное комплексных чисел -1+4i и 4-3i

Answer 1

$\frac{-1+4i}{ 4-3i}= \frac{(-1+4i)(4+3i)}{(4-3i)(4+3i)} = \frac{-4+16i-3i+4*3i^2}{16-9i^2}= \frac{-4-12+13i}{16+9} = \frac{-16+13i}{25}$