4a-3b+2≠0
3a-4b +2 = 24a - 18b +12
21a -14b = -10 ⇒
21a - 14b -20 = -10 - 20 = -30
1)(sin²4x+co²4x-2sin4xcos4x)/(sin4x-cos4x)=(sin4x-cos4x)²/(sin4x-cos4x)=sin4x-cos4x
2)(2sin²3a-sin²3a-cos²3a+2sin3acos3a)/(sin²6a+cos²6a-2sin6acos6a)= (sin²3a-cos²3a+sin6a)/(sin6a-cos6a)²=(-cos6a+sin6a)/(sin6a-cos6a)²=1/(sin6a-cos6a)
(2x-4)²=4x²-16x+16
Если че формулы:
(a+b)²=a²+2ab+b².
(a-b)²=a²-2ab+b².
(2,3a)^2-(7b^3)^2-(2,3a)^2-32,2ab^3-(7b^3)^2= -32,2ab^3-98b^6
Если выражение правильно написана!
Решение
<span>(2x-1)/(2x+0 + (2x+0/(1-2) = 8/(1-4x2)
ОДЗ: 1 - 4x^2 </span>≠ 0
<span> 4x^2 </span>≠ 1
<span>x </span>≠ - 1/2; x ≠ 1/2<span>
</span>- (2x-1)*(2x-1) + (2x+1)*(2x+1)) - 8 = 0
-(4x^2 -4x +1) +(4x^2 + 4x + 1) - 8 = 0
-4x^2 + 4x - 1 + 4x^2 + 4x + 1 - 8 = 0
8x - 8 = 0
8x = 8
x = 1
Ответ: х = 1