Mg = k∆x;
k = mg/∆x = 2*9,8/0,04 = 490 Н/м.
F = k∆x' = 490*0,03 = 14,7 H.
<span>q1=1,3•10-9 Кл</span>
<span>r=<span>0,005 м</span></span>
<span><span>F=<span>2•10-4 Н.</span></span></span>
<span><span><span>e=2</span></span></span>
<span><span><span>k=8.98*10^9</span></span></span>
<span><span><span>---------------</span></span></span>
<span><span><span>q2 - ?</span></span></span>
<span><span><span>решение</span></span></span>
<span><span><span>сила Кулона</span></span></span>
<span><span><span>F= k/e *q1 q2 / r^2</span></span></span>
<span><span><span>q2 = e*r^2*F / (kq1)</span></span></span>
<span><span><span>q2 = 2*0.005^2*2*10-4 / (8.98*10^9*<span>1,3•10-9</span>) = 0.856*10^-9 Кл = 0.856 нКл</span></span></span>
S=a*t^2/2
t=sqrt(2*S/a)=sqrt(2*1000/0,8)=50 c
V=a*t=0,8*50=50 м/с