Question

Сократите дробь: 1) -32b^5c _____ 12b⁴c² 1) 6xy-18x² _______ (y-3x)³

Answer 1

$1) \frac{-32b^5c}{12b^4c^2} =-\frac{-8b}{3c} =- \frac{8b}{3c}$
$2) \frac{6xy-18x^2}{(y-3x)^3} = \frac{6x(y-3x)}{(y-3x)^3} = \frac{6x}{(y-3x)^2}$