,,,,,,,,,,,,,,,,,,,,,,,,,,,
<span><span>NaOH</span>+<span>HCl</span> → <span>NaCl</span>+<span>H2<span>O
</span></span></span><span><span>2<span>NaOH</span></span>+<span>CO2</span> → <span>Na2CO3</span>+<span>H2<span>O
</span></span></span>
Mg+2HCl=MgCl2+H2
n (Mg)=480/24=20 моль
n (H2) теоретический=n (Mg)=20 моль
n (H2) практическ=ωвых×n (H2)теор=0,95×20=19моль
V (H2)=22,4×20=448 л
ничего не будет., наверное