=2NaNO3+Zn(OH)2
=Cu(OH)2+Na2SO4
Решение:
m(C2H5OH) = 20080.8*0.96 = 153,6 г
153,6 г --------------------- х
C2H5OH+ [O] ---> CH3COOH + H2O
46 г ----------------- 44 г
х=146.92 г
m 10%(CH3COOH) = 146.92/0.1 = 1469.2 г.
KOH+H2SO4->K2SO4+2H2O
2KOH+ZnCl2->Zn(OH)2+2KCl
<span>2KOH + CO2 ->K2CO3 + H2O
</span>Cu<span> + </span>2KOH<span> -> </span><span>Cu(OH)2</span><span> + </span>2<span>K
</span>6KOH + P2O5 ->2K3PO4 + 3H2O
4KOH + P2O5 -> 2K2HPO4 + H2O
<span>3KOH + P2O5 ->KH2PO4 + K2HPO4</span>