<span>для сгорания 2 л ацетилена необходимо 5 л кислорода, а для сгорания 10 л ацетилена - 5*5=25л кислорода</span>
CaC2+2H2O-->Ca(OH)2+C2H2
C2H2+H2-->C2H4
C2H4+HOH-->C2H5OH
C2H5OH+O2-->CH3COH+H2O ( kat Ag)
CH3COH+Ag2O-->CH3COOH+2Ag
Fe+2HCl=FeCl2+H2
H2SO4+2NaOH=Na2SO4+2H2O
Ba(NO3)2+Na2SO4=BaSO4+2NaNO3
AlCl3+3NaOH=Al(OH)3+3NaCl
1)
2Cu + O2<span> → 2CuO (нагревание)</span>
CuO + 2HCl → CuCl2<span> + H</span>2O
CuCl2<span> + 2NaOH → Cu(OH)</span>2↓ + 2NaCl
Cu(OH)2<span> → CuO + H</span>2O (нагревание)
CuO + H2SO4<span> → CuSO</span>4<span> + H</span>2O
2)
AlCl3<span> + 3NaOH → Al(OH)</span>3↓ + 3NaCl
2Al(OH)3<span> → Al</span>2O3<span> + 3H</span>2O (нагревание)
Al2O3<span> + 3H</span>2SO4<span> → Al</span>2(SO4)3<span> + 3H</span>2O
Al2(SO4)3<span> + 6KOH → 2Al(OH)</span>3↓ + 3K2SO4
Al(OH)3<span> + HCl → Al(OH)</span>2Cl + H2O
3)
Na2O + H2O → 2NaOH
NaOH + H2SO4<span> → NaHSO</span>4<span> + H</span>2O
2NaHSO4<span> → Na</span>2SO4<span> + H</span>2O + SO3<span>↑ (нагревание)</span>
H2 + CuO -------> H2O + CuM(CuO) = 64 + 16 = 80gM(H2) = 1*2 = 2g80 : 2 = 64 : xx = 1,6 гр