из системы уравнений у=4-x^2 , у=3 получаем x1 =-1 ; x2 = 1
S = [-1;1] ∫ (4-x^2 -3) dx = [-1;1] ∫ (1 -x^2) dx = (x - x^3/3) | [-1;1] =
= (1 - 1^3/3) - (-1 - (-1)^3/3) = 2/3 +2/3 = 4/3 ≈ 1,33