Ca+2HCl= CaCl2+H2
Zn+CuSO=ZnSO4+Cu
2AgNO3=2Ag+2NO2+O2
2AgF+Na2S=Ag2S+2NaF
Na2CO3 + 2 HCl = 2NaCl + CO2 + H2O
V(CO2) = 36 дм3 = 36 л
n(CO2) = 36/22.4 =1.6 моль
n(Na2CO3) = 1.6 моль
M(Na2CO3) = 106 г/моль
m(Na2CO3) = 106 *1.6 =169.6 г
n(HCl) = 2*1.6 = 3.2 моль
M(HCl) = 36.5 г/моль
m(HCl) = 36.5 *3.2 =116.8 г
m(раствора HCl) = 116.8/0.15=778.7 г
V(раствора HCl) = m/p = 778.7/1.072= 726.4 см3
Дано
m(CH3COOH)=120 g
m(C2H5OH)=69 g
---------------------------
m(CH3COOC2H5)-?
120 69 X
CH3COOH+C2H5OH-->CH3COOC2H5+H2O
46 88
M(CH3COOH)=60 g/mol
M(C2H5OH)=46g/mol
n(CH3COOH)=m/M=120/60=2 mol
n(C2H5OH)=m/M=69/46=1.5 mol
n(CH3COOH)>n(C2H5OH)
M(CH3COOC2H5)=88 g/mol
69 / 46 = X/88
X=132 g
ответ 132 г