Question

Помогите найти производнуюf(x)= π/2 -1/sin^2x 10класс

Answer 1

$y= \frac{\pi}{2} - \frac{1}{sin^2x} \\\\(\frac{1}{u})'=-\frac{u'}{u^2}\\\\y'=0-\frac{-2sinx\cdot cosx}{sin^4x}= \frac{2cosx}{sin^3x}$