6.2/31=0.2моль
0,2×5/4=0,25 моль
0,25моль×32г/моль=8г
C + O₂(избыток) = CO₂
C + 4HNO₃ = <span>CO</span>₂<span>↑ + 4NO</span>₂<span>↑ + 2H</span>₂<span>O
C + HCl </span>≠
<span>C + CO</span>₂ = 2CO
<span>C + Na</span>₂SiO₃ ≠
<span>3C + 4Al = Al</span>₄C₃
<span>C + 2H</span>₂SO₄ = CO₂ + 2SO₂ + H₂O<span>
C + 2Cl</span>₂ = CCl₄
1) 2Ba+O2=2BaO
2) BaO+H2O=Ba(OH)2
3) Ba(OH)2+2NaCl=BaCl2+2NaOH
................................................