1. Na₃AsO₄
2. CaOHCl
3. BaSe
4. K₂H₃IO₆
5. Mn₃O₄ (Mn₂O₃·MnO)
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Н3PO4+3NaOH=Na3PO4+3H2O (ортофосфат)
w = n*Mr(э) / Mr(в-в)
Mr=184
w= 2*32/184 = 34.8 (примерно)
Ответ:
Объяснение:
Mr(C6H7N) = 12*6 + 1*7 + 14 =93
W(C) = Ar(C) *n / Mr(C6H7N) *100% = 12*6 / 93 *100% =77%
W(H) = Ar(H) *n / Mr(C6H7N) *100% = 1*7 / 93 *100% = 7%
W(N)= Ar(N) *n / Mr(C6H7N) *100% = 14*1 / 93 *100% =16%
Mr(Li3PO4) = 7*3+31+16*4 = 116
W(Li) = Ar(Li) *n / Mr(Li3PO4) *100% = 7*3 / 116 *100% =18%
W(P) = Ar(P) *n / Mr(Li3PO4) *100% = 31*1 / 116 *100% = 27%
W(O) = Ar(O) *n / Mr(Li3PO4) *100% = 16*4 / 116 *100% = 55%