Хотелось более ясного вопроса
Дано:
<span>ω</span><span>(</span><span>C</span><span>) </span>= <span>52.18</span>%
<span>ω</span><span>(</span><span>H</span><span>) = 1</span><span>3.04</span><span>%</span>
<span>ω</span><span>(</span><span>O</span><span>) = </span><span>34.78</span><span>%</span>
Найти:
Установить формулу-?
Решение:
<span>n</span><span>(</span><span>C</span><span>) : </span><span>n</span><span>(</span><span>H</span><span>) : </span><span>n</span><span>(</span><span>O</span><span>) = 52.18/12 : 13.04/1 : 34.78/16</span>
<span><span> </span><span> </span><span> </span>4.35 : 13.04 : 2,17</span>
<span><span> </span>2 : 6 : 1</span>
<span>C</span><span>₂</span><span>H</span><span>₆</span><span>O</span>
Ответ: <span>C</span><span>₂</span><span>H</span><span>₆</span><span>O</span>
СH3-CH2-CH2OH + [O] =CuO=> CH3-CH2-CHO + HOH
Фосфор имеет валентность равную трем, кислород двум.
P2(III)O3(II)