<span>Li</span>2<span>SiO</span>3<span> + 2NH</span>4<span>NO</span>3<span> + 2H</span>2<span>O --> H</span>2<span>SiO</span>3<span> + 2NH</span>4<span>OH + 2LiNO</span>3
<span>SiO</span>32-<span> + 2NH</span>4+<span> + 2H</span>2<span>O --> H</span>2<span>SiO</span>3<span> + 2NH</span>4<span>OH </span>
<span> </span>
CrCl3 + Cs2SiO3 + H2O =
2CrCl3 + 3Cs2SiO3 + 6H2O --> 2Cr(OH)3 + 3H2SiO3 + 6CsCl
<span>2CrCl</span>3<span> + 3Na</span>2<span>CO</span>3<span> + 3H</span>2<span>O --> 2Cr(OH)</span>3<span> + 3CO</span>2<span> + 6NaCl</span>
<span>2Cr</span>3+<span> + 3CO</span>32-<span> + 3H</span>2<span>O --> 2Cr(OH)</span>3<span> + 3CO</span>2
Дано:
m(C6H6)=40 г
Найти:
m(O2)-?
2 C6H6+15 O2 = 12 CO2↑+6 H2O
n=m/M
M(C6H6)=12*6+1*6=78 г/моль
n(C6H6) = 40 г/78 г/моль = 0,5 моль
n(C6H6) = 0.5 моль
0,5 моль n(O2)
=>
2 15
n(O2)=3.75 моль
m=n*M
M(O2)=16*2 = 32 г/моль
m(O2)=3.75 моль *32 г/моль = 120 г
m(O2)=120 г
Ответ:m(O2)=120 г
2Na+H2 = 2NaH
NaH + H2O = NaOH+H2
NaOH+SO3 = NaHSO4
NaHSO4+NaOH = Na2SO4 + H2O
Na2SO4+Ba(OH)2 = BaSO4 + 2NaOH
2Mg+O2 = 2MgO
MgO + 2HCl = MgCl2 + H2O
MgCl2 + 2AgNO3 = Mg(NO3)2 + 2AgCl
3Mg(NO3)2 + 2Na3PO4 = Mg3(PO4)2 + 6NaNO3
СаСО3 + 2 НСL --> CaCL2 + H2O + CO2 ( v=8,96л),
<span>CO2 + 2NaOH(м=32г) --> Na2CO3 + H2O, </span>
<span>следовательно, м(р-раNaOH)=160г, а v=131мл)</span>