Нужно 6/2=3
х=3 ответ 3 один корень
Ответ ответ ответ ответ ответ ответ ответ
y = -x^(3/2)/sqrt(2)
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y = x^(3/2)/sqrt(2)
Polynomial discriminant:
Δ_x = -108 y^4
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Integer roots:
x = 2, y = ± 2
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x = 8, y = ± 16
x = 18, y = ± 54
x = 0, y = 0
Properties as a function:Domain:
R^2
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Range:
R (all real numbers)
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Partial derivatives:Step-by-step solution
d/(dx)(2 y^2 - x^3) = -3 x^2
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d/(dy)(2 y^2 - x^3) = 4 y
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Indefinite integral:Step-by-step solution
integral(-x^3 + 2 y^2) dx = 2 x y^2 - x^4/4 + constant
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Definite integral over a disk of radius R:
integral integral_(x^2 + y^2<R^2)(2 y^2 - x^3) dx dy = (π R^4)/2
Definite integral over a square of edge length 2 L:
integral_(-L)^L integral_(-L)^L (-x^3 + 2 y^2) dy dx = (8 L^4)/3
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понял?
{3(2х+у-1) = 5х+4у+2
{4(х+2у+1) = 2х-5у+6
{6х+3у-3 = 5х+4у+2
{4х+8у+4 = 2х-5у+6
{6х+3у-3-5х-4у-2 = 0
{4х+8у+4-2х+5у-6 = 0
{х-у-5 = 0 | х - у = 5 | х = 5 + у
{2х+13у-2 = 0
2(5+у) + 13у - 2 = 0
10+2у+13у-2 = 0
15у+8 = 0
15у = -8
у = -8/15
х = 4 7/15
Ответ: (-8/15; 4 7/15)