Solve for x over the real numbers:
x^2+4 = 6-x
Subtract 6-x from both sides:
x^2+x-2 = 0
The left hand side factors into a product with two terms:
(x-1) (x+2) = 0
Split into two equations:
x-1 = 0 or x+2 = 0
Add 1 to both sides:
x = 1 or x+2 = 0
Subtract 2 from both sides:
Answer: |
| x = 1 or x = -2
Удачи!
X²-2x-15=(x-5)(x+3)
x1=5, x2=-3
ili
x1+x2=2, x1.x2=-15
x1=5,x2=-3
А) 3^2
2) 4^2x^2=(4x)^2
3) (2ab)^2
4) (5p^2)^2
5) (m^4n^3k^5)^2
6) (7a^2*2b^3*c^6)^2
Плохо видно, т.к. в машине делала
1 случай - 1 катет х, второй 27-х
2 случай оба катета 27 см