А)Na2O,Ca(OH)2, Ca2CO3,Cu,Mg
б)Na2O,Ca(OH)2,Ca2CO3,Mg
ВАЛЕНТНОСТЬ КРЕМНИЯ В ВЫСШЕМ ОКСИДЕ РАВНА 4 ответ г
<span>ω(N) в NH3 = M(N)/M(NH3) = 14/18*100% = 77.8%
</span><span>ω(S) в H2SO4 = M(S)/M(H2SO4) = 32/98*100% = 32.65%
</span><span>ω(C) в CO2 = M(C)/M(CO2) = 12/44*100% = 27.3 %
</span><span>ω(Na) в NaOH = M(Na)/(NaOH) = 23/40*100% = 57.5%</span>
2РН3+4O2 = P2O5+3Н2O
<span>P2O5 + H2O = 2 HPO<span>3
</span></span>HPO3+H2O=H3PO4