<span>Дано:m(H2O)=18г., V(H2)-?
x 1
2</span>H2+O2=2H2<span>O
2 2
</span>
![n(H2O)=\frac{m}{M}= \frac{m}{2*Mr(H)+Mr(O)} = \frac{18}{2*1+16}= \frac{18}{18} =1 моль](https://tex.z-dn.net/?f=n%28H2O%29%3D%5Cfrac%7Bm%7D%7BM%7D%3D+%5Cfrac%7Bm%7D%7B2%2AMr%28H%29%2BMr%28O%29%7D+%3D+%5Cfrac%7B18%7D%7B2%2A1%2B16%7D%3D+%5Cfrac%7B18%7D%7B18%7D+%3D1+%D0%BC%D0%BE%D0%BB%D1%8C)
<span>Из уравнения составляем пропорцию:
</span><span>
![\frac{x}{2} = \frac{1}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%7D%7B2%7D+%3D+%5Cfrac%7B1%7D%7B2%7D+)
</span>x=1 моль <span>H2
</span>V(<span>H2)=Vm*n=22,4*1=22,4 дм 3
</span>Vm - постоянная величина=<span>22,4 дм 3/моль
</span>Ответ:V(H2)<span>=22,4 дм 3</span>
FeS2= 2H2SO4
m(H2SO4)практ.=1000*0,925=925кг;
m(H2SO4)теорет.=925:0,944=980кг; n(H2SO4)= 980:98=10кмоль; n(FeS2)=5кмоль;m(FeS2)=5*120=600кг;
m(пирита)=600:0,8=750кг
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M(NaCl)=m(р-ра)*ω(NaCl)=320*0,06=19,2 г
m(H2O)=320-19,2=300,8 г