К 2H2O+2e=H2+2OH(-)
a 2Cl(-)-2e=Cl2(0)
BaCl2+2H2O=Cl2+H2+Ba(OH)2
<span> ответ: б) Ba;</span>
ca +h2o-cao + h2 выделение
4г
n=m/M=4/40=0.1 моль
n(h2)=0.1 моль по пропорции
m(h2)=0.1*2=0.2 г
fe +h2so4=feso4 +h2
2al+6hcl=2alcl3 + 3h2
k+h2o=ko +h2
ba+h2o=bao +h2
Ω₁(Na2SO4)=m₁ (Na2SO4)/ m р-ра
0.08= m₁(Na2SO4)/ 60
m₁ (Na2SO4)= 4.8 г
ω₂(Na2SO4)= m₁(Na2SO4)+m₂(Na2SO4)/ m р-ра+m₂(Na2SO4)
ω₂(Na2SO4)=4.8+3.2/ 60+3.2=8/ 63.2= 0.1276 или 12.76%
1)Li2O+SO3=>Li2SO4
<span><span>2)Br2+H2=>2HBr</span></span>
<span>3)2K + 2H2O = 2KOH + H2↑</span>
<span>4)2<span>HNO3+Ba(OH)2=Ba(NO3)2 + 2H20</span></span>
5)Sn(OH)2=SnO+H2O
6)N2+O2=2NO
7)2Al(OH)3=Al2O3+3H2O
8)CaO+H2O=Ca(OH)2
Вроде так.:)
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1. C₃H₈ + Cl₂ → C₃H₇Cl + HCl
2. C₃H₇Cl + NaOH → C₃H₇OH + NaCl