<span>Na + Cl→ <span>Na<span>Cl
</span></span></span><span><span>3 Mg</span> + <span>2 <span>H3PO4</span></span> → <span>Mg3<span>(PO4)</span>2</span> + <span>3 <span>H2
</span></span></span><span><span>2 Al</span> + <span>3 <span>H2SO4</span></span> → <span>3 <span>H2</span></span> +<span><span>(SO4)</span><span>3
</span></span></span><span>Mg + <span>H2SO4</span> → <span>MgSO4</span> + <span>H<span>2
</span></span></span><span><span>Fe<span>(OH)</span>3</span> + <span>3 <span>HNO3</span></span> → <span>Fe<span>(NO3)</span>3</span> + <span>3 <span>H2<span>O
</span></span></span></span><span><span>Fe2O3</span> + <span>6 <span>HCl</span></span> → <span>2 <span>FeCl3</span></span> + <span>3 <span>H2<span>O
</span></span></span></span><span><span>3 <span>MgO</span></span> + <span>2 <span>H3PO4</span></span> → <span>Mg3<span>(PO4)</span>2</span> + <span>3 <span>H2<span>O
</span></span></span></span><span>Au + <span>H2SO4</span> → <span>Ø
</span></span><span><span>NaCl</span> + <span>HNO3</span> → <span>NaNO3</span> + <span>H<span>Cl</span></span></span>
<span>4 Fe(NO3)3 => 2 Fe2O3 + 12 NO2 + 3 O2</span>
Помоги мне я помогу тебе <span>Трикутники АВС і КРН рівносторонні й АВ = КР
Знайдіть КН, якщо ВС = 5 см Даю</span>
FeSO4 +2H2O⇒эл,ток 2Fe +O2 +H2SO4
2H2O⇒эл,ток 2H2 +2O2
m=k I t k(Fe)=1.0424г/А*ч m=1,0424г/А*ч *13,4А *1ч=13,968г
13,968г-----100\%
хг---------75\% х=10,48г Fe
CnH(2n-6)
0,9 = 12n/(14n-6)
n = 9
<span>C9H12</span>