1)(16b²+40b+25+32b²-50+16b²-40b+25)/(16b²-40b+25+16b²+40b+25+50-32b²)=
=(64b²-25)/100
2)x≠1
(√x-3)(√x-1)=(√x+2)(√x+1)
x-√x-3√x+3-x-2√x-√x-2=0
-7√x=-1
√x=1/7
x=1/49
Х-у=4:1/3 х+у=2:1/4
х-у=12 х+у=8
х-у+х+у=12+8
2х=20
х=10
соответсвенно у=-2
10*(-2)=-20
<span>решите уравнение 10(х-7)=-3(а+х)-23</span>
<span>10x-70=-3a-3x-23</span>
<span>10x+3a+3x=70-23</span>
<span>13x+3a=47</span>
x=(47-3a)/13