Na2SO4 + HCl -> H2SO4 + NaCl
2Na+ + SO4 2- -> 2H+ +SO42- +Na+ + Cl-
2KMn⁺⁷O₄ + 10KI⁻ + 8H₂SO₄ = 2Mn⁺²SO₄ + 6K₂SO₄ + 8H₂O + 5I₂⁰
Mn⁺⁷ +5e⁻ = Mn⁺² | 2 - окислитель, процесс восстановления
2I⁻ - 2e⁻ = I₂⁰ | 5 - восстановитель, процесс окисления
<span>2Ca</span><span> +O2 ---></span><span> 2</span><span>CaO</span>
<span><span>CaO</span><span> +H2O----> </span><span> </span><span>Ca(OH)2</span></span>
<span><span><span>Ca(OH)2</span><span> +H2CO3---></span><span> </span><span>CaCO3+2H2O</span></span></span>
<span><span><span><span>CaCo3---><span> CaO+CO2</span></span></span></span></span>
<span><span><span><span><span><span>CaO+2HCl---></span><span> </span><span>CaCl2+H2O тут наверно у тебя ошибка не<span> </span><span>Cal2 аCaCl2</span></span></span></span></span></span></span>
<span><span><span><span><span><span><span><span>CaCl2</span><span> +2AgNO3---> 2</span><span>AgCI+ Ca(NO3)2</span></span></span></span></span></span></span></span>
Ω = m(соли) / (m(соли) + m(H2O)) * 100%
0,2 = 50 / (50 + х)
0,2 * (50 + х) = 50
10 + 0,2х = 50
0,2х = 50 - 10
0,2х = 40
х = 200, в)
Ответ: m(H2O) = 200 г