Question

Lim(9-x^2)/(√3x-3) x стремится к 3

Answer 1

$\lim_{n \to 3} \frac{9-x^2}{\sqrt{3x}-3}=\lim_{n \to 3} \frac{(9-x^2)(\sqrt{3x}+3)}{(\sqrt{3x}-3)(\sqrt{3x}+3)}=\lim_{n \to 3} \frac{(9-x^2)(\sqrt{3x}+3)}{3x-9}=\\=-\lim_{n \to 3} \frac{(x-3)(x+3)(\sqrt{3x}+3)}{3(x-3)}=-\lim_{n \to 3} \frac{(x+3)(\sqrt{3x}+3)}{3}=-\frac{(3+3)(3+3)}{3}=\\=-12$