Question

Решите уравнение: 5)(3/5)^(x2-x)=(5/3)^-2

Answer 1

$1)\\ \\ 27^{3x-1}=\frac{1}{9}^{x}\\ \\ (3^3)^{3x-1}=(3^{-2})^{x}\\ \\ 3^{9x-3}=3^{-2x}\\ \\ \Rightarrow 9x-3=-2x\\ \\ 9x-3+2x=0\\ \\ 11x=3\\ \\ \boxed{x=\frac{3}{11}}$

$2)\\ \\ 5^{3x}+3 \cdot 5^{3x-2}=140\\ \\ 5^{3x-2} \cdot 5^{2}+3 \cdot 5^{3x-2}=140\\ \\ 5^{3x-2} (5^{2}+3)=140\\ \\ 5^{3x-2} \cdot 28=140\\ \\ 5^{3x-2}=140:28\\ \\ 5^{3x-2}=5^{1}\\ \\ \Rightarrow 3x-2=1\\ \\ 3x=1+2\\ \\ 3x=3\\ \\ x=3:3\\ \\ \boxed{x=1}$

$3)\\ \\ 4^{x}-2^{x}-12=0\\ \\ (2^{2})^{x}-2^{x}=12\\ \\ 2^{2x}-2^{x}=12\\ \\ 2^{x}(2^{2}-1)=12\\ \\ 2^{x} \cdot 3=12\\ \\ 2^{x}=12:3\\ \\ 2^{x}=4\\ \\ 2^{x}=2^{2}\\ \\ \Rightarrow \boxed{x=2}$

$5)\\ \\ (\frac{3}{5})^{x^{2}-x}=(\frac{5}{3})^{-2}\\ \\ (\frac{3}{5})^{x^{2}-x}=[(\frac{3}{5})^{-1}]^{-2}\\ \\ (\frac{3}{5})^{x^{2}-x}=(\frac{3}{5})^{2}\\ \\ \Rightarrow x^{2}-x=2\\ \\ x^{2}-x-2=0\\ \\ \Delta=b^{2}-4ac\\ \\ a=1;~b=-1;~c=-2\\ \\ \Delta=(-1)^{2}-4\cdot1\cdot(-2)\\ \\ \Delta=1+8=9\\ \\ x_{1,2}=\frac{-b \pm \sqrt{\Delta}}{2a}\\ \\x_{1,2}=\frac{-(-1) \pm \sqrt{9}}{2\cdot1}\\ \\ x_{1,2}=\frac{1 \pm 3}{2}\\ \\ x_{1}=\frac{1+3}{2}=\frac{4}{2}=2\\ \\ x_{2}=\frac{1-3}{2}=\frac{-2}{2}=-1\\ \\ x \in \{ -1;~2 \}$