y³-3y²+9y+3y²-9y+27-y³+6y = 0
6y+27 = 0
6y = -27
y = -27/6 = -9/2
y = -4.5
Решение
ctg(x/2 - π/3)=√3
x/2 - π/3 = arcctg√3 + πk, k ∈ Z
x/2 - π/3 = π/6 + πk, k ∈ Z
x/2 = π/6 + π/3<span> + πk, k ∈ Z
</span>x/2 = π/2 <span>+ πk, k ∈ Z
</span>x = π<span> + 2πk, k ∈ Z</span>
корней нет,потому что D=-8