ZnO+2Na=Na2O+Zn не пойму, при чем тут гидрометаллаургия. Если бы из соли цинка, тогда да
<span>m(C</span>6<span>H</span>14<span>) = 1 кг = 1000 г</span>
<span>n(C</span>6<span>H</span>14<span>) = m(C</span>6<span>H</span>14<span>) / M(C</span>6<span>H</span>14<span>) = 1000 / 86 = 11.63 моль</span>
<span>2C</span>6<span>H</span>14<span> + 19O</span>2<span> → 12CO</span>2<span> + 14H</span>2<span>O</span>
<span>n(O</span>2<span>) = (19/2) * n(C</span>6<span>H</span>14<span>) = (19/2) * 11.63 = 110.5 моль</span>
<span>V(O</span>2<span>) = n(O</span>2<span>) * V</span>м<span> = 110.5 * 22.4 = 2474 л</span>
<span>ϕ(О</span>2<span>) = 21\% = 0.21</span>
<span>V(воздуха) = V(O</span>2<span>) / ϕ(О</span>2<span>) = 2474 / 0.21 = 11783 л ≈ </span>11.8 м3<span> </span>
<span>KOH - K2O,Ca(OH)2 -CaO,H2SO3 - SO2,H3PO4 - P2O5</span>