<span>Дано: </span>
<span>m(NaOH) = 80г</span>
<span>w(NaOH) = 0.052</span>
<span>Найти:</span>
<span>m(Mg(OH)2) - ?</span>
Решение:
<span>2NaOH+MgCl2=2NaCl+Mg(OH)2</span>
mв-ва(NaOH) = m(р-ра)*w(в-ва) = 80*0,052 = 4,16г
n(NaOH) = m(NaOH)/M(NaOH) = 4.16/40 = 0.104моль
n(Mg(OH)2) = 1/2 *n (NaOH) = 0.104/2 = 0.052моль
m(Mg(OH)2) = n(Mg(OH)2)*M(Mg(OH)2) = 0.052*41 = 2.132г