Mr(CaCr2O7) = Mr = 7Ar(O) + Ar(Ca) + 2Ar(Cr) = 7 * 16 + 1 * 40 + 2 * 52 = 256
w(O) = 7Ar(O) / Mr = 112 / 256 = 0.4375 = 43.75%
w(Ca) = Ar(Ca) / Mr = 40 / 256 = 0.15625 = 15.625%
w(Cr) = 2Ar(Cr) / Mr = 104 / 256 = 0.40625 = 40.625%
Ответ:
32 г.
Объяснение:
решение во вложении:......⤴
P2O5+H2O=2HPO3
n P2O5=10/142=0.07 моль
n HPO3=(0.07*2)*0.8=0.11 моль
m HPO3=80*0.11=8.8 г
1-г, 2-е, 3-б, 4-а.........
СH3-COH + H2 -> CH3-CH2-OH (p, kat)
CH3CH2OH -> CH2=CH2 + H2 ( t>140, H2SO4)
CH2=CH2 + HCl -> CH3-CH2-Cl
CH3-CH2-Cl + 2Na + Cl-CH2-CH3 -> CH3-CH2-CH2-CH3 + 2NaCL