<span>task/28177870
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Найти производную функции
1 . y=(x+9)</span>⁴<span>/ (x-3) 2. y=x*sin(3x-π/2)
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</span>1.
* * * ( u / v) ' =( u ' *v - u *v ' ) / v² * * *
y ' = ((x+9)⁴/ (x-3) ) ' = (4(x+9)³ (x-3) - (x+9)⁴ *1) / (x-3)² .
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2.
* * * (uv) ' = u ' *v + u*v ' ; sin(3x-π/2)= - sin(π/2 - 3x) = - cos3x * * *
y ' ( x*sin(3x-π/2)' = (- x* cos3x ) ' = - ( x* cos3x ) ' =
- ( 1*cos3x +x*(-sin3x)*(3x) ' ) = 3sin3x - cos3x .
sin (arccos (-12/13)) решить.
X=2, y=-2
x=5, y=4
x=-1, y=-8
y=-8, x=-1
y=2, x=4
y=-12, x=-3
Система:
х-5<x/6 |*6 6x-30<x 6x-x<30 5x<30 | :5
6-0.6x≤1.4x <=> -0.6x-1.4x≤-6 <=> -2x ≤-6 | :(-2) x≥3
Cистема:
х<6
х≥3
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----*---------o----->x
3 6
Ответ:x∈ [3; 6)
cos(30°+a)-cos(30°-a) = cos30cosa-sin30sina - (cos30cosa+sin30sina)