<span>СН4(4)
</span><span>CH3Cl(4
</span>CH2<span>Cl2 (4
</span><span>CHCl3(4
</span>CCl4(4
W%(Ca)=40/56 *100=71,43%
m(Ca)=0,7143*112=80г
CH4 + Cl2 = CH3Cl + HCl
CH3Cl + NaOH = CH3OH + NaCl
CH3OH + CuO= Cu + HCHO + H2O
HCHO+2[Ag(NH3)2]OH=HCOOH+2Ag+4NH3+2H2O
<span>2HCOOH +O2 = 2CO2 + 2H2O
</span>
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Кто владеет информацией, тот владеет миром.