7^2x-3=49
7^2x-3=7^2
2x-3=2
2x= 2+3
2x=5
x=2/5
x=2,5
1 мин 25 с =85с 1 ч 1 мин 30 с =3690 с 3 мин 27 с =207с
![\frac{ log_{4}(16x^4)+11 }{ log_{4} ^{2}x-9 } \geq -1 \\ \\](https://tex.z-dn.net/?f=+%5Cfrac%7B+log_%7B4%7D%2816x%5E4%29%2B11+%7D%7B++log_%7B4%7D+%5E%7B2%7Dx-9+%7D++%5Cgeq+-1+%5C%5C++%5C%5C+)
одз
{x>0
{x≠64
{x≠1/64
![\frac{log_{4} 16+4 log_{4}x+11+ log_{4} ^{2}x-9 }{(log_{4}x-3)(log_{4}x+3)} \geq 0 \\ \\ \frac{log_{4} ^{2}x+4log_{4}x+4}{(log_{4}x- log_{4}64 )(log_{4}x- log_{4} \frac{1}{64} )} \geq 0 \\ \\ \frac{(log_{4}x-log_{4} \frac{1}{16} )^2}{(log_{4}x- log_{4}64 )(log_{4}x- log_{4} \frac{1}{64} )} \geq 0 \\ \\ \frac{(x- \frac{1}{16})^2 }{(x-64)(x- \frac{1}{64}) } \geq 0 \\ \\](https://tex.z-dn.net/?f=+%5Cfrac%7Blog_%7B4%7D+16%2B4+log_%7B4%7Dx%2B11%2B++log_%7B4%7D+%5E%7B2%7Dx-9++%7D%7B%28log_%7B4%7Dx-3%29%28log_%7B4%7Dx%2B3%29%7D+++%5Cgeq+0+%5C%5C++%5C%5C++%5Cfrac%7Blog_%7B4%7D+%5E%7B2%7Dx%2B4log_%7B4%7Dx%2B4%7D%7B%28log_%7B4%7Dx-+log_%7B4%7D64+%29%28log_%7B4%7Dx-+log_%7B4%7D+%5Cfrac%7B1%7D%7B64%7D++%29%7D++%5Cgeq+0+%5C%5C++%5C%5C++%5Cfrac%7B%28log_%7B4%7Dx-log_%7B4%7D+%5Cfrac%7B1%7D%7B16%7D+%29%5E2%7D%7B%28log_%7B4%7Dx-+log_%7B4%7D64+%29%28log_%7B4%7Dx-+log_%7B4%7D+%5Cfrac%7B1%7D%7B64%7D++%29%7D++%5Cgeq+0+%5C%5C++%5C%5C++%5Cfrac%7B%28x-+%5Cfrac%7B1%7D%7B16%7D%29%5E2+%7D%7B%28x-64%29%28x-+%5Cfrac%7B1%7D%7B64%7D%29+%7D++%5Cgeq+0+%5C%5C++%5C%5C+)
+++++(1/64)-----------[1/16]---------(64)
x∈(-∞;1/64)U{1/16}U(64;+∞)
с учетом одз получаем ответ
x∈(0;1/64)U{1/16}U(64;+∞)
Обгоны будут проходить в 2 разных точках зарание незачто