Question

Решите пожалуйста!!! Дам 100 баллов! Фото прилагается.Решите пожалуйста!!! Дам 100 баллов! Фото прилагается.

Answer 1

1) $14 \frac{7}{15}-3 \frac{9}{23}* \frac{23}{27}-1 \frac{1}{45}* \frac{1}{6}= \frac{217}{15}- \frac{78}{27}- \frac{23}{135}= \frac{1953-390}{135}- \frac{23}{135}=$$\frac{1540}{135}=11 \frac{11}{27}$

2) $8 \frac{1}{3}*9-4 \frac{1}{3}*3 \frac{1}{4}-12 \frac{2}{7}*3 \frac{5}{24}=75- \frac{169}{12}- \frac{473}{12}=75-25 \frac{1}{3}=49 \frac{2}{3}$

3) $1 \frac{1}{48}*2 \frac{2}{5}-(9 \frac{1}{6}* \frac{4}{15}+2 \frac{5}{9})* \frac{2}{5}= \frac{49*12}{48*5}-( \frac{55*4}{6*15}+ \frac{23}{9})* \frac{2}{5}= \frac{49}{20}-2=$$2 \frac{9}{20}-2= \frac{9}{20}=0,45$

4) $(2 \frac{1}{4}+4 \frac{5}{6}):3 \frac{2}{5}- \frac{3}{4}: \frac{3}{5}=( \frac{9}{4}+ \frac{29}{6})* \frac{5}{17}- \frac{5}{4}= \frac{25}{12}- \frac{15}{12}= \frac{10}{12}= \frac{5}{6}$

5) $(5 \frac{8}{9}:1 \frac{17}{36}+1 \frac{1}{4})* \frac{5}{21}=( \frac{53}{9}* \frac{36}{53}+ \frac{5}{4})* \frac{5}{21}= \frac{21*5}{4*21}= \frac{5}{4}=1,25$

6) $(4 \frac{2}{5}* \frac{5}{8}+12 \frac{3}{7}:4 \frac{5}{6}-8 \frac{1}{2}:14): \frac{33}{56}= \frac{22*5}{5*8}+ \frac{87*6}{7*29}- \frac{17}{28})* \frac{56}{33}=$$( \frac{22}{8}+ \frac{18}{7}- \frac{17}{28})* \frac{56}{33}= \frac{154+144-34}{56}* \frac{56}{33}= \frac{264}{33}=8$

7) $(3,04: \frac{1}{30}-16,03: \frac{7}{20})* \frac{1}{5}+0,072* \frac{1}{3}= \frac{304*3 - 229*2}{10*5}+0,024=$$9,08+0,024=9,104$

8) $(-28,6:57,2-26,8:(-1,34))*(-3,1)=(-0,5+20)*(-3,1)=$$-60,45$

9) $(-1,7+3,64:(-1,4)):(-0,001)*(-0,4)=(-1,7-2,6)*1000*0,4$$=-4,3*400=-1720$

10) $(- \frac{5}{12}+ \frac{11}{6}):(- \frac{13}{72})= \frac{-20+33}{48}*( \frac{72}{13})=$$- \frac{13*72}{48*13}= - \frac{72}{48}=- \frac{6}{4}=-1,5$

11) $( \frac{9}{14}-(- \frac{5}{21})):(-2 \frac{9}{14})= \frac{27+10}{42}*(- \frac{14}{37})=- \frac{14}{42}=- \frac{1}{3}$