Question

Помогите, пожалуйста
решите номер 4

Answer 1

2³/₈xⁿ⁺¹yᵃ⁺³*(4/19)x⁴ⁿ⁻²y⁵ᵃ⁻¹=(19/8)xⁿ⁺¹yᵃ⁺³*(4/19)x⁴ⁿ⁻²y⁵ᵃ⁻¹=

=(1/2)x⁽ⁿ⁺¹⁺⁴ⁿ⁻²⁾y⁽ᵃ⁺³⁺⁵ᵃ⁻¹⁾=(1/2)x⁵ⁿ⁻¹y⁶ᵃ⁺²=x^(5n-1)*y^(6m+2)/2.

Answer 2

$2 \frac{3}{8} {x}^{n + 1} {y}^{m + 3} \times \frac{4}{19} {x}^{4n - 2} {y}^{5m - 1} = \frac{19}{8} \times \frac{4}{19} {x}^{n + 1 + 4n - 2} {y}^{m + 3 + 5m - 1} = \frac{1}{2} {x}^{5n - 1} {y}^{6m + 2}$