Question

Найдите значение выражения 27+108b+108

Answer 1

$b=-\frac{4}{9}\; ;\\\\ \frac{27b^2+108b+108}{b} :(\frac{6}{b}+3)= \frac{27(b^2+4b+4)}{b} :\frac{6+3b}{b}=\\\\= \frac{27(b+2)^2}{b} \cdot \frac{b}{3(2+b)} = \frac{27(b+2)}{3} =9(b+2)=9(-\frac{4}{9}+2)=\\\\=9\cdot \frac{-4+18}{9}=14$