Mr(H₂SO₄)=98 г\моль
w(H) =
![\frac{2}{98}*100](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B98%7D%2A100)
<span>%=2%</span>
w(S)=
![\frac{32}{98}*100](https://tex.z-dn.net/?f=+%5Cfrac%7B32%7D%7B98%7D%2A100)
%=32%
w(O)=
![\frac{64}{98}*100](https://tex.z-dn.net/?f=+%5Cfrac%7B64%7D%7B98%7D%2A100)
%= 65%
Mr(NaOH)=23+16+1=40г\моль
w(Na)=
![\frac{23}{40}*100](https://tex.z-dn.net/?f=+%5Cfrac%7B23%7D%7B40%7D%2A100)
%= 57,5%
w(O)=
![\frac{16}{40}*100](https://tex.z-dn.net/?f=+%5Cfrac%7B16%7D%7B40%7D%2A100)
%= 40%
w(H)=
![\frac{1}{40} *100](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B40%7D+%2A100)
%=2,5%
CL2+2Na-->2NaCL
2NaCL+H2SO4-->2HCL+Na2SO4
2HCL+Mg-->MgCL2+H2
MgCL2+2Ag-->2AgCL+Mg
N2+3H2-->2NH3
NH3+H2O-->NH4OH
2NH4OH+H2SO4-->(NH4)2SO4+2H2O
(NH4)2SO4+2NaOH-->Na2SO4+2NH3+2H2O
N(S)=n(SO2)=4 моль
m(S)=4*32=128 г
Ответ: m(S)=128 г
M(CxHy)=Vm*P = 22,4*2,59=58г/моль
масса 1 моль 58гр.
m(C)=58*0,8=46,4г;
m(H)=58*0,2=11,6г;
m(CxHy)=46,4+11,2=57,6гр.
M(СnH2n+2)=14n+2
14n+2=58
n=4
Ответ: С4Н10