2cos2x +3sinx cosx=0 cos^2 x=(1+cos2x)/2
2*(2cos^2 x-1) +3sinx cosx=0
4cos^2 x-2+3sinx cosx=0
4cos^2 x +3sinx cosx -2(sin^2 x+cos^2 x)=0
2cos^2 x+3sinx cosx -2sin^2 x=0 /:cos^2 x
2+3tgx-2tg^2 x=0
2tg^2 x-3tgx-2=0
y=tgx; 2y^2-3y-2=0; D=9-4*2*(-2)=25=5^2; y1=(3-5)/4=-1/2;; y2=8/4=2
tgx=-1/2 ili tgx=2
x=-arctg0,5+πn x=arctg2+πk; n,k-celoe
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Ответ: решение смотри на фотографии
Объяснение:
0,2a(8a² - 3)(15a² + 2) = 0,2a(120a⁴ + 16a² - 45a² - 6) = 0,2a(120a⁴ - 29a² - 6) =
= 24a⁵ - 5,8a³ - 1,2a
(х+5)³-(х+1)³=4(3х²-5)
72х+124=-20
72х=-20-124
72х=-144
х=-2
(х-3)³-х²(х+6)=5х(5-3х)
27х-27=25х
27х-25х=27
2х=27
х=27/2=13.5