Question

Сократите дробь 3-√3 / √6-√2

Answer 1

$\frac{3- \sqrt{3} }{ \sqrt{6} - \sqrt{2} } = \frac{( \sqrt{3}) ^{2} - \sqrt{3} }{ \sqrt{3*2}- \sqrt{2} }= \frac{ \sqrt{3}( \sqrt{3}-1) }{ \sqrt{2} ( \sqrt{3} -1)}= \frac{ \sqrt{3} }{ \sqrt{2} } = \frac{ \sqrt{3}* \sqrt{2} }{ \sqrt{2}* \sqrt{2} } = \frac{ \sqrt{6} }{2}$