ОДЗ x>5
х-5>=2²
x-5>=4
x>=4+5
x>=9
![\left\{ {{6x-y=2} \atop {-x+y=1}} \right.](https://tex.z-dn.net/?f=+%5Cleft%5C%7B+%7B%7B6x-y%3D2%7D+%5Catop+%7B-x%2By%3D1%7D%7D+%5Cright.+)
из второго уравнения y=1+x
подставляем в первое, получаем
6x-(1+x)=2
решаем
6x-1-x=2
5x=3
x=
![\frac{3}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B5%7D+)
y=1+
![\frac{3}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B5%7D+)
y=1
![\frac{3}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B5%7D+)
Ответ: x=
![\frac{3}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B5%7D+)
; y=1
![\frac{3}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B5%7D+)
16x-5∠2x+11
16x-2x∠11+5
14x∠16
x∠16\14
x∠8\7
1) >
2) =
3) >
4) >
5) <
6) <
7) <
8) >
9) >
10) =
11) >
12) >