Стоимость – c, цену – a, количество – n ,цена=стоимость: количество стоимость=цена* количество <span>количество=стоимость : цену
70*4=280
1600:200=8
960:8=120</span>
1) Log(5) (3)V(5^24 * 5^56 * 5) = Log(5) (3)V(5^(24 + 56 + 1) = Log(5) (3)V(5^81) = Log(5) 5^(81/3) = Log(5) 5^27 = 27
2) (3)V(Log(2) 16^30 * 32) = (3)V(Log(2) (2^4)^30 * 2^5) = (3)V(Log(2) 2^120 * 2^5) = (3)V(Log(2) 2^(120 + 5)) = (3)V(Log(2) 2^125) = (3)V125 = 5
3) (3)V(Log(3) (3)V(81^20 * 3)) = (3)V(Log(3) (3)V(3^80 * 3) = (3)V(Log(3) (3)V3^81 = (3)V(Log(3) 3^(81/3) = (3)V(Log(3) 3^27 = (3)V27 = 3
4) (3)V( Log(17) (4)V(17^38 * 17^70) = (3)V( Log(17) (4)V(17^(38 + 70)) = (3)V( Log(17) (4)V17^108) = (3)V( Log(17) 17^(108/4) = (3)V( Log(17) 17^27 = (3)V27 = 3
5) V(Log(19) (4)V(19^54 * 19^90) = V(Log(19) (4)V(19^(54 + 90)) = V(Log(19) (4)V19^144 = V(Log(19) 19^(144/4) = V(Log(19) 19^36 = V36 = 6
6) V(Log(3) (3)V(27^56 * 27^19) : 3) = V(Log(3) (3)V(27^75) : 3) = V(Log(3) (3)V(3^225) : 3) = V(Log(3) 3^75 :3) = V(75 : 3) = V25 = 5
7) V(Log(2) V(32^21 * 32^48 * 32^3) : 5) = V(Log(2) V32^72 : 5) = V(Log(2) V2^360 : 5) = V(Log(2) 2^(360/2) : 5) = V(Log(2) 2^180 : 5) = V(180 : 5) = V36 = 6
(3)V - корень третьей степени
(4)V - корень четвертой степени
Log(5) - логарифм по основанию пять
Купила- 6 яб.
съела- 2 яб.
осталось- ?• яб.
6-2=4(яб.) осталось
Ответ: 4 яблока
1. 3x = 1/27; x = (1/27)/3;
x = 1/81.
2. 4x = 16; x = 16/4;
x = 4.
3. 4x = 1/64; x = (1/64)/4;
x = 1/256.
4. 4x = 1/4; x = (1/4)/4;
x = 1/16.
5. 5x = 1/25; x = (1/25)/5
x = 1/125.
6. 5x = 1/625; x = (1/625)/5
x = 1/3125
7. 5x = 125; x = 125/5
x = 25.
8. 6x = 1/36; x = (1/36)/6
x = 1/216.
9. 7x = 1/49; x = (1/49)/7
x = 1/343.
10. 7x = 49; x = 49/7
x = 7.