Const
n = 10;
m = 10;
var i, j, column, row, sum_column, sum_row: integer;
arr: array [1..n,1..m] of integer;
begin
for i :=1 to n do
begin
for j:=1 to m do
begin
arr[i,j]:= random()*10;
end;
end;
readln(row);
readln(column);
sum_column:= 0;
sum_row := 0;
for i:=1 to n do
begin
sum_row := sum_row + arr[i,row];
end;
for j:=1 to m do
begin
sum_column := sum_column + arr[column, j];
end;
writeln(sum_column);
writeln(sum_row);
end.
Не проверено. Написал сходу в окне.
1)function first(k,l,m,n:integer):boolean;
begin
if (((k mod 2=0) and (l mod 2<>0)) or ((l mod 2=0) and (k mod 2<>0)))=(((m mod 2=0) and (n mod 2<>0)) or ((n mod 2=0) and (m mod 2<>0))) then first:=true else first:=false;
end;
2)function second(k,l,m,n:integer):boolean;
<span> begin
if (k=m) or (l=n) or (((k+1)=m) and ((l+1)=n)) or (((k+2)=m) and ((l+2)=n)) or (((k+3)=m) and ((l+3)=n)) or (((k+4)=m) and ((l+4)=n)) or (((k+5)=m) and ((l+5)=n)) or (((k+6)=m) and ((l+6)=n)) or (((k-1)=m) and ((l-1)=n)) or (((k-2)=m) and ((l-2)=n)) or (((k-3)=m) and ((l-3)=n)) or (((k-4)=m) and ((l-4)=n)) or (((k-5)=m) and ((l-5)=n)) or (((k-6)=m) and ((l-6)=n)) or (((m+1)=k) and ((n+1)=l)) or (((m+2)=k) and ((n+2)=l)) or (((m+3)=k) and ((n+3)=l)) or (((m+4)=k) and ((n+4)=l)) or (((m+5)=k) and ((n+5)=l)) or (((m+6)=k) and ((n+6)=l)) or (((m-1)=k) and ((n-1)=l)) or (((m-2)=k) and ((n-2)=l)) or (((m-3)=k) and ((n-3)=l)) or (((m-4)=k) and ((n-4)=l)) or (((m-5)=k) and ((n-5)=l)) or (((m-6)=k) and ((n-6)=l)) or (((k-1)=m) and ((l+1)=n)) or (((k-2)=m) and ((l+2)=n)) or (((k-3)=m) and ((l+3)=n)) or (((k-4)=m) and ((l+4)=n)) or (((k-5)=m) and ((l+5)=n)) or (((k-6)=m) and ((l+6)=n)) or (((k-1)=m) and ((l+1)=n)) or (((k-2)=m) and ((l+2)=n)) or (((k-3)=m) and ((l+3)=n)) or (((k-4)=m) and ((l+4)=n)) or (((k-5)=m) and ((l+5)=n)) or (((k-6)=m) and ((l+6)=n)) or (((m-1)=k) and ((n+1)=l)) or (((m-2)=k) and ((n+2)=l)) or (((m-3)=k) and ((n+3)=l)) or (((m-4)=k) and ((n+4)=l)) or (((m-5)=k) and ((n+5)=l)) or (((m-6)=k) and ((n+6)=l)) or (((m-1)=k) and ((n+1)=l)) or (((m-2)=k) and ((n+2)=l)) or (((m-3)=k) and ((n+3)=l)) or (((m-4)=k) and ((n+4)=l)) or (((m-5)=k) and ((n+5)=l)) or (((m-6)=k) and ((n+6)=l)) then second:=true else second:=false;
<span> end;</span></span>
(x+y+z)/3 = 0,(3)x+0,(3)y+0,(3)z
Var x1,y1,z1,x2,y2,z2,x3,y3,z3,abx,aby,abz,acx,acy,acz,s,mx,my,mz,c:real;
begin;
readln(x1);
readln(y1);
readln(z1);
readln(x2);
readln(y2);
readln(z2);
readln(x3);
readln(y3);
readln(z3);
abx:=x2-x1;
acx:=x3-x1;
aby:=y2-y1;
acy:=y3-y1;
abz:=z2-z1;
acz:=z3-z1;
mx:=aby*acz-abz*acy;
my:=abz*acx-abx*acz;
mz:=abx*acy-aby*acx;
c:=sqrt(sqr(mx)+sqr(my)+sqr(mz));
s:=0.5*c;
writeln(s);
end.<span>
</span>