Question

Решить: 4sin2x*cos2x=1

Answer 1

$4sin2x*cos2x=1; \\ 2*2sin2x*cos2x=1; \\ sin (2*2x)=\frac {1}{2}; \\ sin (4x)=\frac {1}{2}; \\ 4x=(-1)^k \frac{\pi}{6}+pi*k;\\ x=(-1)^k \frac{\pi}{24}+\frac {pi*k}{4};$

k є Z