Question

Помогите решить 15a/5-a + 6a/a^2-25 • 7a + 35/3 / - дробь

Answer 1

$\frac{15}{5-a}+ \frac{6a}{ a^{2}-25 } * \frac{7a+35}{3} = -\frac{15}{a-5}+ \frac{6a}{(a-5)(a+5)}* \frac{7(a+5)}{3}= -\frac{15}{a-5}+ \frac{14a}{a-5}= \\ \frac{14a-15}{a-5}$