Mr(Ba(OH)2)=137+(16+2)*2=173г/моль
3.
Mr(SO)=32+16=48
W(S)=32/48=0.67=67%
W(O)=16/48=0.33=33%
Mr(SO2)=32+2*16=64
W(S)=32/64=0.5=50%
W(O)=32/64=0.5=50%
Mr(SO3)=32+3*16=80
W(S)=32/80=0.4=40%
W(O)=48/80=0.6=60%
С2H5COOC3H7 или, если струкурной формулой, CH3-CH2 -CO-O-C3H7
Ω(C)=53,33\%
ω(N)=31,11\%
ω(H)=15,56\%
CxNyHz
x : y : z = 53,33/12 : 31,11/14 : 15,56/1 = 4,44 : 2,22 : 15,56 = 2 : 1 : 7
Ответ: C2H7N<span />