10 л Х л
C3H8 + 5O2 = 3CO2 + 4H2O
n= 1 моль n = 5 моль
Vm=22,4 л/моль Vm = 22,4 л/моль
V = 22,4 л V = 112 л
10 л С3Н8 - Х л О2
22,4 л С3Н8 - 112 л О2
V(O2) = 10 * 112 / 22,4 = 50 л
M(Na2CO3) = 106 г/моль
n = m/M = 10,6/106 = 0,1 моль
1)CO2+H2O=H2CO3(слабая кислота, сразу же распадается на CO2 и H2O)
2)N2O5+H2O=2HNO3
3)SO2+H2O=H2SO3( малоустойчива)
4)SO3+CaO=CaSO4
5)<span>Na2O+2HCl=2NaCl+H2O</span>
1) 2KHCO3<span> + H</span>2SO4<span> → K</span>2SO4<span> + 2H</span>2O + 2CO2↑
2K+<span> + 2HCO</span>3-<span> + 2H</span>+<span> + SO</span>42-<span> → 2K</span>+<span> + SO</span>42-<span> + 2H</span>2O + 2CO2↑
HCO3-<span> + H</span>+<span> → H</span>2O + CO2↑
2) Zn(OH)2<span> + 2NaOH → Na</span>2[Zn(OH)4]
Zn(OH)2<span> + 2Na</span>+<span> + 2OH</span>-<span> → 2Na</span>+<span> + [Zn(OH)</span>4]2-
Zn(OH)2<span> + 2OH</span>-<span> → [Zn(OH)</span>4]2-
3) CaCl2<span> + 2AgNO</span>3<span> → Ca(NO</span>3)2<span> + 2AgCl↓</span>
Ca2+<span> + 2Cl</span>-<span> + 2Ag</span>+<span> + 2NO</span>3-<span> → Ca</span>2+<span> + 2NO</span>3-<span> + 2AgCl↓</span>
Ag+<span> + Cl</span>-<span> → AgCl↓</span>