Question

ПОМОГИТЕЕЕЕЕ ПОЖАЛУЙСТААА АЛГЕБРААА ДАЮ 17 баллов

Answer 1

$2x:\frac{3x^2}{x-4}=\frac{2x(x-4)}{3x^2}=\frac{2(x-4)}{3x}\\\\\frac{5x+15}{3x-15}:\frac{3x+9}{x^2-25}=\frac{5(x+3)}{3(x-5)}\cdot \frac{(x-5)(x+5)}{3(x+3)}=\frac{5(x+5)}{9}\\\\\frac{7x-14}{(x-3)^2}:\frac{2x-4}{x^2-9}=\frac{7(x-2)}{(x-3)^2}\cdot \frac{(x-3)(x+3)}{2(x-2)}=\frac{7(x+3)}{2(x-3)}$