<span>4Al+3O2= 2Al2O3
</span><span>Na2O+2HCL = 2NaCl+H20
</span><span>2K+H2SO4=K2SO4+ H2</span>
Ar(I2)=127×2=254 n(I2)=12,7/254=0,05моль и тогда число молекул N=6×10²³×0,05=3×10²²
1. w(F) = (213/233) * 100\% = 91.4\%
2. n(Cl) = 3680/35.5 = 103.7 моль
V(Cl) = 103.7 * 22.4 = 2322.88 л
3. n(F) = 8.45 * 10^22 / 6.02 * 10^23 = 0.14 моль
V(F) = 0.14 * 22.4 = 3.136 л
1) HNO = H⁺ + NO₃⁻
2) Ca(OH)₂ = CaOH⁺ + OH⁻, CaOH⁺ = Ca²⁺ + 2OH⁻
3) Al(NO₃)₃ = Al³⁺ + 3NO₃⁻
4) CuCl₂ = Cu²⁺ + 2Cl⁻
5) K₂SO₄ = 2K⁺ + SO₄²⁻
6) Na₃PO₄ = 3Na⁺ + PO₄³⁻